# Line slope calculator x+4y=29

**Straight line given by points A[5; 6] and B[9; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.25x+7.25

**Canonical form of the line equation:**x+4y-29 = 0

**Parametric form of the line equation:**

x = 4t+5

y = -t+6 ; t ∈ R

**Slope:**m = -0.25

**Slope angle of line: φ =**-14°2'10″ = -0.245 rad

**X intercept:**x

_{0}= 29

**Y intercept:**y

_{0}= q = 7.25

**Distance line from the origin:**d

_{0}= 7.0335

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; -1)

**Normal vector: n =**(1; 4)

**Midpoint of the segment AB: M =**[7; 5.5]

**Perpendicular Bisector equation:**4x-y-22.5 = 0

**Vector OA = (5; 6) ; |OA| = 7.8102**

**Vector OB = (9; 5) ; |OB| = 10.2956**

**Scalar product OA .OB = 75**

**Angle ∠ AOB = 21°8'23″ = 0.369 rad**