# Line slope calculator 4x+y=10

**Straight line given by points A[0; 10] and B[1; 6]**

## Calculation:

**Slope-intercept form of line:**y = -4x+10

**Canonical form of the line equation:**4x+y-10 = 0

**Parametric form of the line equation:**

x = t

y = -4t+10 ; t ∈ R

**Slope:**m = -4

**Slope angle of line: φ =**-75°57'50″ = -1.3258 rad

**X intercept:**x

_{0}= 2.5

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 2.4254

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; -4)

**Normal vector: n =**(4; 1)

**Midpoint of the segment AB: M =**[0.5; 8]

**Perpendicular Bisector equation:**x-4y+31.5 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (1; 6) ; |OB| = 6.0828**

**Scalar product OA .OB = 60**

**Angle ∠ AOB = 9°27'44″ = 0.1651 rad**